Question

One day,I ask the son of my close friend about his age. The son replied in different way:- he said that one year ago, my dad was 8 times as old as me and now his age is equal to the square of my age. Represent the above situation in the form of a quadratic equation.

Answer 1

let the present age of son be x and age of father be y
ATQ
y= 8(x-1)
y= x^2

then putting eqn 1 in 2
8x - 7 = x^2
x^2-8x+8=0
x= 4

Answer 2

Answer:

$x^2-8x+7=0$

Step-by-step explanation:

We are given that now Father's age is equal to the square of my age.

Let the present age of Son be x

So, father's present age = $x^2$

1 year ago

Father'age = $x^2-1$

Son's age = x-1

We are given that one year ago, my dad was 8 times as old as me

$x^2-1=8(x-1)$

$x^2-1=8x-8$

$x^2-8x+7=0$

Hence he above situation in the form of a quadratic equation is $x^2-8x+7=0$