One day Lalita took seven rounds of a rectangular park of length 450m and breadth 275 m. The next day she took five rounds of another rectangular park of length 500m and breadth 300 m. Which day did she walk more and by how much?
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Answered by
6
Step-by-step explanation:
Perimeter of first day rectangular park = 2(l+b)
=2(450m+275m)
=2(725)
=1450m
Perineter of second day rectangular park=2(l+b)
=2(500+300)
=2(800)
=1600m
Second day she walked more compared to first day
i. e, 1600-1450 = 150m
Hope it helps u
Answered by
2
Answer:
Lalita took 7 rounds on first day around rectangular park
perimeter of rectangle =2*(L+B)
=2*(450m + 275m)
=2*725m
=1450m
she took 5 rounds around another rectangular park
=2*(500m+300m)
=2*800m
=1600m
in 1450m and 1600m .1600m is greater
1600m-1450m=150m
so,she walk more in next day by 150m
Step-by-step explanation
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