one day the minimum temperature in Kolkata were recorded as 80.8 degree fahrenheit what does the temperature in degree Celsius on that day
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Temperature in °F =80.8
Therefore,
Temperature in °C = ( 80.8°F - 32) * 5/9
=27.1111111111111°C
Therefore,
Temperature in °C = ( 80.8°F - 32) * 5/9
=27.1111111111111°C
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