Question

please answer the question guys fast

Answer 1

The abscissa of point A is (-3) and lies in II quadrant.

The abscissa of point B is 5 and lies in IV quadrant.

Answer 2

Answer:

Step-by-step explanation:

X=3+root 2 - root 3

Therefore x^2=(3)^2+[(root 2-root3)]^2+2 (3)(root 2-root3 )

X^2=9+[(root 2)^2+(root 3)^2-2 (root2)(root3)]+6 (root2 -root 3)

=9+[2+3- 2(root6)]+6root2-6root3

=9+2+3-2root6+6root2 -6root3

=14-2root6+6root2 -6root3

Now...

6x=6 (3+root 2-root3 )

=18+6root2 -6root3

Now...we have to do...

x^2-6x+6....

Putting value

=14-2root6 +6root2 -6root3 -18-6root2 +6root3 +6

......+6root2...-6root2...+6root3...-6root3...will b cancelled out...

=14-2root6-18+6

=2-2root6 ans.