Question

One end of a uniform wire of length L and of weight W is attached rigidly to a point in the roof and a weight W_(1) is suspended from its lower end. If S is the area of cross-section of the wire, the stress in the wire at a height 3 L/4 from its lower end is

Answer 1

Net force acting at desired point is given by-

Net force = Load + 3/4th of weight of wire

$\large \bf F= w_1 - \frac{3}{4} w$

Area of cross – section = S

Stress in the wire at given point is-

$\boxed{ \bf Stress = \frac{ Force }{ Area}}$

$\underline{ \boxed{ \green{ \bf Stress = \frac{ W_1 + \frac{3}{4}W}{S} }}}$