Question

one end of an iron wire offline 250 cm and of diameter 1 millimetre is rigidly fixed to the beam and weight of 8 kg is placed at the other end calculate the elongation of the wire .Y of iron =20 *10^11 dyne cm^2 and g =980 unit​

Answer 1

ANSWER  :

Given,

g=9.8m/s  

2  

m=8kg

l=4m

D=2mm

r=1mm=1×10 -3 m

Y=2×10  

11

Nm  

−2  

Young's modulus of the iron wire,

Y=  Δl/l F/A

Δl=l  

Yπr  

2mg  

Δ=4×  

2×10  

11 ×3.14×(1×10 −3 )  2  

8×9.8  

Δl=0.5mm

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Explanation: