Question

One end of massless rope, which passes over a massless and frictionless pulley P is tied to a hook C while the other end is free. Maximum tension that the rope can bear is 360 N. With what value of maximum safe acceleration (in ms⁻²) can a man of 60 kg moves downwards on the rope? [Take g = 10 ms⁻²](a) 16 (b) 6(c) 4 (d) 8

Answer 1

Answer:

B) ms⁻²

Explanation:

Maximum tension of the rope = 360N  ( Given )

Movement downwards = 60kg ( Given )

Equation of motion for m1 = Fnet =T-m1g = m1a

Equation of motion for m2 = Fnet =T-m2g = m2a

wherein -

a = [ m2-m1]g/m1+m2

a = 2m1m2g/ m1+m2

T – 60g = 60a or  

960 – (60 × 10) = 60a or

60a = 360 or  

a = 6ms⁻²

Thus, the value of maximum safe acceleration is 6.

Answer 2

Answer: 4 m/s^2

Explanation:

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