Question

Two blocks are connected over a massless pulley as shown in fig. The mass of block A is 10 kg and the coefficient of kinetic friction is 0.2. Block A slides down the incline at constant speed. The mass of block B in kg is:(a) 3.5 (b) 3.3(c) 3.0 (d) 2.5

Answer 1

Answer:

B) 3.3kg

Explanation:

Mass of block A = 10kg (Given)

coefficient of kinetic friction = 0.2  (Given)

When the forces on block A in the plane of the incline, will be added -

T - Ff - W  

Where the force of friction is given by  

Ff = ukN =uk (mAgcos∅)

The component of the weight in the direction of the incline is given by  -

W = mA}gsin∅  

Solving for the tension, T, we find  

T = mAg (sin 30° -ukcos 30°)

Since,   T - mBg = 0 , thus

mB = mA  (sin 30° -ukcos 30°)

or  

mB  =  3.3 kg

Thus, The mass of block B in kg is 3.3kg

Answer 2

Explanation:

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