Question

One equation of a pair of dependent linear equations is –5x + 7y – 2 = 0. The second equation can be

(A) 10x + 14y + 4 = 0                                                

(B) –10x – 14y + 4 = 0

(C) –10x + 14y + 4 = 0                                  

(D) 10x – 14y = –4


Two numbers are in the ratio 5 : 6. If 8 is subtracted from each of the numbers, the ratio becomes 4 : 5. Then the numbers are:

(A) 40, 42                                           

(B) 42, 48

(C) 40, 48                                           

(D) 44, 50


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Answer 1

Answer:

I know only 2nd one

Step-by-step explanation:

2) let the numbers be 5x,6x

given, (5x-8)/(6x-8) = 4/5

=> 25x-40 = 24x-32

=> x = 8

so, the numbers are 40,48