one exterior angle of triangle is 110 degree and the interior angle are in rario of 6:5. Find the angle of triangle
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let the sides be X
6x +5x = 110
11x =110
x=110/11 = 10
6x= 6*10 =60
5x= 5*10=50
so the third side is 60+50+x= 180
110+x=180
x=180-110=70
6x +5x = 110
11x =110
x=110/11 = 10
6x= 6*10 =60
5x= 5*10=50
so the third side is 60+50+x= 180
110+x=180
x=180-110=70
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