one fifth of a number exceeds one fifth of its succeeding number by 3 .find the number.
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Let the number is xx
\therefore \dfrac{1}{4}(x)-\dfrac{1}{5}(x+1)=3∴
4
1
(x)−
5
1
(x+1)=3
\Rightarrow \dfrac{5x-4(x+1)}{20}=3⇒
20
5x−4(x+1)
=3
\Rightarrow 5x-4x-4=60⇒5x−4x−4=60
\therefore x=64∴x=64.
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One-fourth of a number exceeds one-fifth of its succeeding number by 3; find the number. ∴ x = 64 \therefore x=64 ∴x=64
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