one fifth of sum is 20 and half of the difference is 6
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Let there be two positive integers x and y
Thus
x + y / 5 = 20
x + y = 100
&
x - y / 2 = 6
x - y = 12
Thus then solving by any of the method for example by elimination method
we get x = 56 and y = 44.
Thus
x + y / 5 = 20
x + y = 100
&
x - y / 2 = 6
x - y = 12
Thus then solving by any of the method for example by elimination method
we get x = 56 and y = 44.
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