One fifthof a number exceeds one seventh of the same number by 10. The number is
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let the no. be x
therefore,
x/5=x/7+10
=>x/5-x/7=10
=>(7x-5x)/35=10
=>2x=350
thus, x=175
verification:
x/5=175/5=35
x/7=175/7=25
A/Q,
x/5=x/7+10
thus,
35=25+10
so,
L.H.S=R.H.S
therefore,
x/5=x/7+10
=>x/5-x/7=10
=>(7x-5x)/35=10
=>2x=350
thus, x=175
verification:
x/5=175/5=35
x/7=175/7=25
A/Q,
x/5=x/7+10
thus,
35=25+10
so,
L.H.S=R.H.S
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