one forth of a number exceeds one fifth of its succeeding number by 3 .Find the number?
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let the number be x.
1/4th of x= x/4
its succeeding number = x+1
1/5th of x+1= x+1/5
a/q x/4 + 3 = x+1/ 5
= x/4 - (x+1)/ 5 = -3
= (5x - 4x- 4)/ 20 = -3
= x - 4 = -3*20
= x= -60 +4
∴ x = -56
so the number is -56.
1/4 of - 56 = -14
1/5 of -55 = -11
-14 exceeds -11 by 3
1/4th of x= x/4
its succeeding number = x+1
1/5th of x+1= x+1/5
a/q x/4 + 3 = x+1/ 5
= x/4 - (x+1)/ 5 = -3
= (5x - 4x- 4)/ 20 = -3
= x - 4 = -3*20
= x= -60 +4
∴ x = -56
so the number is -56.
1/4 of - 56 = -14
1/5 of -55 = -11
-14 exceeds -11 by 3
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