One-fourth of a pole is painted red, two-fifth is painted blue and the remaining 21 m is painted green. Find the height of the pole. (A) 40 m (B) 60 m (C) 80 m (D) 90 m
Answers
Answered by
3
Answer:
80 cm
Step-by-step explanation:
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Answered by
3
Answer:
Option (B)
Step-by-step explanation:
Solution :-
Let the total height of the pole be X m
The portion which is painted red = 1/4 of X
=> (1/4)×X
=> X/4 m
The portion which is painted blue = 2/5 of X
=> (2/5)×X
=> 2X/5 m
Total portion of the pole which is painted red and blue = (X/4)+(2X/5)
LCM of 4 and 5 = 20
=> (5X+8X)/20
=> 13X/20 m
Remaining portion = Total height - coloured portion
=> X-(13X/20)
=> (20X-13X)/20
=> 7X/20 m
According to the given problem
Remaining portion = 21 m
=> 7X /20 = 21
=> 7X = 21×20
=> 7X = 420
=> X = 420/7
=> X = 60 m
Therefore, X = 60 m
Answer:-
Total height of the pole = 60 m
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