Question

one glass has juice and water in the ratio 5:2 while other glass has them in ratio 7:4 respectively. if both glasses poured in a vessel then what will be final ratio of water to juice in the vessel?

Answer 1

Answer: The final ratio of water to juice in the vessel is 25:52.

Step-by-step explanation:

Since we have given that

Ratio of juice and water in one glass  = 5:2

Ratio of juice and water in other glass = 7:4

According to question, both glasses poured in a vessel.

We need to find the final ratio of water to juice in the vessel.

So, ratio of juice to water becomes,

$\dfrac{5}{7}+\dfrac{7}{11}:\dfrac{2}{7}+\dfrac{4}{11}\\\\=\dfrac{55+49}{77}:\dfrac{22+28}{77}\\\\=\dfrac{104}{77}:\dfrac{50}{77}\\\\=104:50\\\\=52:25$

Hence, the final ratio of water to juice in the vessel is 25:52.

Answer 2

Answer:

The final ratio of water to juice in the vessel is 52:25.

Step-by-step explanation:

Given: juice and water in the ratio 5:2 while other glass has them in ratio 7:4 respectively both glasses are mixed.

The fraction of juice in one glass  = 5/7

The fraction of water in one glass=2/7

The fraction of juice in other glass=7/11

The fraction of water in other glass=4/11

According to the question:

So, when both are poured then the ratio of juice to water becomes

$\frac{5}{7} +\frac{7}{11}=\frac{2}{7}+\frac{4}{11}$

$\frac{55+49}{77} :\frac{22+28}{77} \\\\104:50\\52:25$

Hence, the final ratio of water to juice in the vessel is 52:25.

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