One gram mole of a gas occupies 22.4 l at ntp this fact was derieved from
Answers
Answered by
1
P V = nRT
T= 293.18
P=1 atm
V= 1x0.0821 x 293 / 1
V=24.0553 l
T= 293.18
P=1 atm
V= 1x0.0821 x 293 / 1
V=24.0553 l
Similar questions