One gram mole of a substance contains 6.022 x 1023 molecules. 1. 24 g of carbon is treated with 72 g of oxygen to form CO2. Identify the limiting reagent. 2. Find the number of molecules of CO2 formed in this situation.
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Answer:
Explanation:
One mole of any substance contains 6.022×10
23
atoms/molecules. Number of molecules of H
2
SO
4
present in 100mL of 0.02M H
2
SO
4
solution is __________?
Medium
Answer
Correct option is
A
12.044×10
20
molecules
Moles of H
2
SO
4
= Molarity of H
2
SO
4
× Volume of solution (L)
=0.02×0.1
=2×10
−3
moles
No. of H
2
SO
4
molecules =2×10
−3
×6.022×10
23
=12.044×10
20
molecules
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