One gram of Na3AsO4 is boiled with excess of solid Kl in presence of strong HCI. The iodine evolved is absorbed in Kl solution and titrated against 0.2 N hyposolution. Assuming the reaction to be
AsO 3- + 2H+ + 2I- → (AsO3)³- + H2O + I²
calculate the volume of hypo consumed, [Atomic weight of As = 75]
(A) 48.1 mL
(B) 38.4 mL
(C) 24.7 ml
(D) 30.3 mL
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Answer:
48.1 ml
Explanation:
n-factor for As =5−3=2
Equivalent weight of Na 3 AsO4 = 208/2=104
Normality of Na 3 AsO4 = mass /eq.wt = 1/104
we know that (thiosulphate) N 1 V 1 =N 2 V2 (Na3 ASO 4 )
0.2×V 1 = 1/104 ×1000
v1 =48.1ml Ans
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