Question

one gram of NaCl is dissolved in 10 gram of a solution the density of which is 1.0 gram/CC find molality and molarity of NaCl​

Answer 1

Answer:

Explanation:

Density = mass solution/ volume of solution

V = 10g/1.07 = 9.34 mL

molarity == 0.02 mol/9.34 x 10–3L = 2.1

mass solution- mass of solute= mass solvent

10g - 1 = 9g

molality= 0.02 mol/0.009 =2.2

Answer 2

Answer:

Explanation:

Number of moles of nacl_ 1/molar mass of nacl

1/58.44 - 0.017111

Density - mass/volume

Volume- mass / density

10/1.07- 9.34 ml

Change in litre _ 0.00934L

Molarity- moles of solute/volume of solution in litre

-0.017111/0.00934

- 1.829 M

& mass of solution - mass of solute

- mass of solvent

- 10g - 1g - 9g

Change in kg - 0.009kg

Molality- mass of solute/ mass of solvent in kg

- 0.017111 / 0.009 - 1.899m