Question

one gram of water at 80° c mixed with one gram of ice at 0° c the resultant temperature is

Answer 1

Answer:

Its probably the mean of the temperatures of the substances. Therefore, mean temperature is 0+80/2=40. So it should ney 40°c .

Answer 2

Answer:0°c water

Explanation:

Let T be final temperature

ml+ms∆t=ms∆t

80×(1gm)+1×1×T=1×1×(80-T)

T=0