One hundred men in 10 days do one third of a piece of work. The work is then required to be completed in another 13 days. On the next day (the eleventh day) 60 more men are employed. How many men must be discharged at the end of the 18th day so that the rest of the men, working for the remaining time, will just complete the work in time?
Answers
Given : 100 Men in 10 days One hundred men in 10 days do one third of a piece of work. The work is then required to be completed in another 13 days. On the next day (the eleventh day) 60 more men are employed.
To find : How many men must be discharged at the end of the 18th day so that the rest of the men, working for the remaining time, will just complete the work in time?
Solution:
One hundred men in 10 days do one third of a piece of work.
100 men work in 10 Days = 100 * 10 = 1000 man days
It is 1/3 of Work
Hence total work = 3000 man days
Remaining work = 3000 - 1000 = 2000 man days
To be completed in 13 more days total 23 Days
from 11th to 18th - 8 days
Men = 100 + 60 = 160 Days
Work done = 160 * 8 = 1280 Man days
Work Left = 2000 - 1280 = 720 Man Days
Days left = 13 - 8 = 5 or (23 - 18 = 5)
Men required = 720/5 = 144
Men to be discharged = 160 - 144 = 16
16 Men to be discharged at the end of 18th day
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