Question

one
If x=(-7) is on root- kx² - 7x + 8 = 0
then find the value of (k)





plzz solve quickly​

Answer 1

Since, 2 is root of the kx ...

2

−7x+6=0

⇒k(2)

2

−7×2+6=0

⇒4k−14+6=0

⇒4k=8

⇒k=2 -: Answer...

Answer 2

let f(x)=-kx²-7x+8

x=-7

f(-7)=-k(-7)²-7(-7)+8

0=-49k+49+8

49k=57

k=57/49

I hope this answer may help you dear