Question

One integer is 2 more than 5 times another integer. If the difference of the two integers is 26, what is the smaller integer?

Answer 1

Let

Smaller integer = y

Larger integer = x

one integer is 2 more than 5 times another

x=2+5y...........(1)

difference of the two integers is 26

x-y=26...........(2)

Put the value of x from (1) to (2)

2+5y-y=26

4y=26-2

4y=24

4y/4=24/4

y=6

Put the value of y in (2)

x-6=26

x=26+6

x=32

Smaller integer = y = 6

Answer 2

Answer:

6, 32

Step-by-step explanation:

Let, the integers be $x$ and $y$.

According to the problem,

$y = 5x + 2 -----equation 1$

$y - x = 26$

$y = 26 + x ------equation 2$

Substitute equation 2 in 1

$26 + x = 5x + 2$

$4x = 24$

$x = 6$

$y = 26 + 6 = 32$

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