Question

the velocity time graph of a particle moving along a straight line is shown in the figure the displacement of the particle in 5 second is:​

Answer 1

Answer:

4 m

Explanation:

the displacement will be the addition of the areas of the certain Triangle(AOB)+{-(CBD)}+EDGF.

so,for ∆AOB =1/2×3×2=3 unit square

for ∆CBD=1/2×1×2=1 unit square

for EDGF=1×2=2 unit square

so,the displacement=3-1+2=4 unit

Answer 2

Hope this should help out