Question

one is asked to say a one digit number. find the probability of it being a multiple of 3?​

Answer 1

Answer:

AASDFUKOLLKJHGGG XXVGHHJKLLLLLLLLL HJJNMMMLL

Answer 2

Answer:

A three digit number starts from 100 and ends to 999. So, the numbers that are multiple of 6 are

102,108,114,120,126,…..996

As we know that, T(subscript)n=a+(n-1)d

996=102+(n-1)6

996=96+6n

6n=996–96

6n=900

n=900/6=150

n=150

So there are 150 numbers between 100 & 999 which are multiples of 6.

And the total numbers of three digit numbers=900

Probability of getting a 3 digit number between 100 & 999 which is multiple of 6=

150/900=15/90=5/30=1/6