One is asked to say a two digit number. What is the probability of
a) Both digits being same
b) The first digit being twice the second
Answers
Answer:
here is the answer!!
Hence, the required probability is 24/90 = 4/15
Step-by-step explanation:
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Given : One is asked to say a two digit number.
To Find : the probability of
a) Both digits being same
b) The first digit being twice the second
Solution:
two digit numbers from 10 to 99
Hence Total 90 numbers are possible
Both Digits being same
11 , 22 , 33 , 44 , 55 , 66 , 77 , 88 , 99
There are 9 such numbers possible
Probability of Both digits being same = 9/90 = 1/10
The first digit being twice the second
21 , 42 , 63 , 84
Hence 4 such numbers possible
Probability of first digit being twice the second = 4 /90
= 2/45
Probability of Both digits being same = 1/10
Probability of first digit being twice the second = 2/45
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