Math, asked by adwaithsabu11, 1 month ago

One is asked to say a two digit number. What is the probability of
a) Both digits being same
b) The first digit being twice the second

Answers

Answered by TokyoLights
5

Answer:

here is the answer!!

Hence, the required probability is 24/90 = 4/15

Step-by-step explanation:

XxLovingboiXx

Answered by amitnrw
4

Given :  One is asked to say a two digit number.  

To Find : the probability of

a) Both digits being same

b) The first digit being twice the second

Solution:

two digit numbers  from 10 to 99  

Hence Total 90 numbers are possible

Both Digits being same

11 , 22 , 33 , 44 , 55 , 66 , 77 , 88 , 99

There are 9 such numbers possible

Probability of   Both digits being same =   9/90  =  1/10

The first digit being twice the second

21 , 42 , 63 , 84

Hence  4   such numbers possible

Probability of   first digit being twice the second  = 4 /90

= 2/45

Probability of   Both digits being same =   1/10

Probability of   first digit being twice the second  =   2/45

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