Question

Physics Question :-

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A Stimulator moves from rest to a speed of 2500 m/s in 25 seconds. What is the magnitude of Stimulator acceleration?
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Answer 1

Answer:

Research simulations

Explanation:

Quantum mechanics is a field in physics that attempts to explain the natural forces at the atomic and subatomic level. ... Quantum physicists can use simulations to test out theories about the interaction of subatomic particles, such as quarks and gluons.

Answer 2

★ Given :

» Initial velocity of Stimulator (u) = 0

» Final velocity of Stimulator (v) = 2500m/s

» Time taken by Stimulator (T) = 25sec

★ Need to FinD :

➟ Magnitude of Stimulator acceleration?

★ Formula UseD Here :

• ➣ v = u + at

⚘ Where :

• ➮ v = Final velocity
• ➮ u = Initial velocity
• ➮ a = acceleration
• ➮ t = Time taken

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☆ UnderstanDing the concept :

➣ For solving this question whe have to apply 1st equation of motion. After putting value in formula we can easily calculate the acceleration of Stimulator !

✇ Putting value in formula :

• ↪ v = u + at
• ↪ 2500m/s = 0 + a × 25s
• ↪ 2500 = 0 + 25a
• ↪ 2500 = 25a
• ↪ a = 100 m/s²

✧ Therefore :

• ➮ Acceleration of Stimulator is 100m/s²

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