Question

One kg of ice at 0 degree centigrade is mixed with 1kg of water at 10 degree centigrade. What is the resulting temperature?
(A)Between 0 and 10 degree centigrade
(B)Greater than 10 degree centigrade
(C)Lesser than 0 degree centigrade
(D)Equal to 0 degree centigrade
-Pls give a proper explanation-

Answer 1

Specific heat of water is 1 cal/g. There is totally 1kg, so it possesses 1000cal of energy. Now, since ice is already at 0 Celsius, it needs latent heat to turn into water. This energy is provided by the water. Latent heat of ice is 80cal/g. So, for 1kg, it requires 8000cal. But water only possess 1000cal of energy. So, only certain mass of ice will get converted into water at 0C, and the rest of the water at 10C will cool down to 0C also. But, since only 1000cal is available, part of the ice remains as ice. So, temperature in the end is 0 Celsius.

Answer 2

Answer:

Explanation:

Heat required to convert 1kgof ice at 0 deg to water at 0 deg is 80X1000=80000cal

But heat to change 1kg of water at 10 deg to 0 deg is only 10000Cal. So this heat is not sufficient to convert the ice at 0deg to water at 0 deg. ie the mixture will be at 0deg