One kilogram of ice at -10°c is heated at a constant rate until, at temperature of 80°c.
how mush heat is required? Specific latent heat of ice 336 1/g, specific heat capacity of ice -2.1 1/g °c, specific heat capacity of water 4.2 1/g°
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Explanation:
first energy to convert ice at -0° to Ice at 0
Q=mcΔΦ
where Φ is temperature
Q= 1kg × 2110j/kg × (0-(-10))
Q= 21100j
then, energy to convert ice at 0° to water at 0°
Q=ml
Q= 1kg× 33600
Q= 33600j
then energy to convert water at 0° to water at 80°
Q=mcΔΦ
Q= 1 × 4200 × (80-10)
Q= 29400j
total energy
21100+33600+29400
84100joules
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