One
lit of sample of hard water
contains 0.0333 gm of
of Cacl2 , and
0.060 gm
of Mason. Calculate
the total, hardness
hardness of the
water
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Answer:
mole of CaCl
2
≡1 mole of CaCO
3
≡1 mole of MgCl
2
∴ 100mg CaCO
3
is produced by 95mg MgCl
2
∴ 1mg of MgCl
2
gives
95
100
mg CaCO
3
= 1.05mg CaCO
3
Similarly, 1mg of CaCl
2
gives
111
100
mg CaCO
3
= 0.90mg CaCO
3
∴ Total CaCO
3
per litre of water= 1.05+0.90=1.95 mg
Weight of 1000ml of water= 10
3
g=10
6
mg
∴ Total hardness in terms of parts of CaCO
3
per 10
6
parts of water by weight =
10
6
1.95
×10
6
=1.95 ppm
Answer: (A) 1.954 ppm
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