Chemistry, asked by aakashbhatia030, 1 year ago

One litre of a gas at stp weight 1.16 g it can possible be
(a) C2H2
(b) CO
(c) O2
(d) CH4

Answers

Answered by kokan6515
151
At STP
1 litre of gas = 1.16g
22.4L of gas =1.16gm×22.4= 25.98g.m ≈26gm

M.M of C2H2=26gm
M.M of CO =28gm
M.M of O2 = 32gm
M.M of CH4 =16gm

So it is clear that it is ethyne gas.
Option A is correct

aakashbhatia030: How did you covert 22.4 L to 26 gm
kokan6515: multiplying
aakashbhatia030: Thanks☺️
Answered by kobenhavn
25

Answer: (a) C_2H_2

Explanation:

According to Avogadro's law, 1 mole of every gas occupies 22.4 L at STP and weighs equal to its molar mass.

Thus if 1 L of gas weighs= 1.16 g

22.4 L of gas weighs=\frac{1.16}{1}\times 22.4=26g

Thus the molar mass of the gas is 26 g.

Molar mass of C_2H_2 is 26 g

Molar mass of CO is 28  g

Molar mass of O_2 is 32 g

Molar mass of CH_4 is 16 g

Thus the gas is C_2H_2.


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