Question

one litre of gas weights 1.33 gram at 750 mm of HG and 77 degree Celsius calculate the weight of 500 ml of the gas at 37 degree Celsius and 640 mm of HG

Answer 1

We know from Ideal gas equation if no. of moles to be constant then,
P1V1T1=P2V2T2
Now, substitute P1=800/760 =1.05 atm, P​​2 =400/7460=0.52 atm, T1=270K ,​T2=273K, V1=10000L, V2=V
P1V1T1=P2V2T2V2=P1V1T2T1P2V=1.05x10000x273270x0.52=20416.6L
Now, no. of cylinders required = 20416.6/10=2042 (nearly)