Question

one litre of Oxygen gas under STP will weigh
1.43g
22.4g
11.2g
22.4g

Answer 1

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Moles of oxygen = volume in litre or dm^3/volume at STP

Moles of oxygen = mass/ molar mass

mass/molar mass = Volume in litre /Volume at STP

Mass of oxygen = Volume in litre / volume at STP × molar mass

: . Molar mass of oxygen = O2 = 16×2 = 32g/mol

Mass of oxygen = 1 /22.4 × 32

Mass of oxygen = 0.044 ×32

Mass of oxygen = 1.42 g

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Answer 2

Answer:

The weight of one liter of oxygen under STP is equal to 1.43g.

Explanation:

Volume of 1 mole of oxygen gas under STP = 22.4L

Therefore,

22.4L of oxygen gas under STP has $= 32 g$

Weight of 1L of oxygen gas   $=\frac{32}{22.4}=1.43g$

Therefore  the option (1) is correct.