Question

one litre of sea water weighs 1050 g and contains 6 * 10 -3 g of oxygen gas. calculate the concentration of the dissolved oxygen in ppm.

Answer 1

Parts per million = Number of parts of a component x 10^6 / Total number of parts of all components in a solution

Hence, concentration of the dissolved oxygen in ppm

= 6×10^−3g x 10^6 / 1050 g

= 5.71 ppm

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Answer 2

Answer:

The concentration of the dissolved oxygen in ppm is 6 mg/L.

Explanation:

Mass of oxygen =$6\times 10^{-3} g=6 mg$

1 mg = 0.001 g

Volume of the sea water =  1 L

$ppm=\frac{\text{mass of solute in mg}}{\text{volume of the solution in L}}$

$ppm=\frac{6 mg}{1L}=6 mg/L$

The concentration of the dissolved oxygen in ppm is 6 mg/L.