One mole enantiomertically pure CH3CH2CH2 CH2 BrCH3 is reacted with one mole Br2 at 300 K. The number of possible chiral products formed is 1) 3 2) 6 3) 5 4) 7
Answers
Answered by
2
Step-by-step explanation:
For bromination at 1st carbon, 2nd carbon will be chiral
on 3rd carbon produce two compounds, one towards the observer and one away from him both are chiral
on 4th carbon produce meso form and gives 1 chiral
on brominating at 5th also one chiral at the 2nd carbon position
We get a total of 5 chiral
Similar questions