Question

One mole of a non ideal gas undergoes a change
of state (2.0 atm, 3.0 L, 95 K) → (4.0 atm,
5.0 L, 245 K) with a change in internal energy
AU = 30.0 L atm. The change in enthalpy of the
process in L atm is
(1) 40.0
(2) 42.3
(3) 44.0
(4) 56.0​

Answer 1

One mole of a non ideal gas undergoes a change

of state (2.0 atm, 3.0 L, 95 K) → (4.0 atm,

5.0 L, 245 K) with a change in internal energy

AU = 30.0 L atm. The change in enthalpy of the

process in L atm is

(1) 40.0

(2) 42.3

(3) 44.0✔️✔️✔️

(4) 56.0

Answer 2

Answer:

44 Latm

Explanation:

P1 = 2 atm

P2 = 4 atm

V1 = 3 L

V2 = 5 L

∆H = ∆U + ∆(PV)

∆H = 30 + (P2V2 – P1V1)

∆H = 30 + (4×5 – 2×3)

∆H = 30+ (20 – 6)

∆H = 30 + 14

∆H = 44 L atm