One mole of ab reacts with one mole of cd then equilibrium constant
Answers
Answered by
0
To calculate an equilibrium constant the reaction must be a reversible reaction.
Let's consider A+B=C a reversible reaction.
Let the initial concentrations of A and B be '1'. There will be ‘0’ concentration of product as the state is initial.
Now at equilibrium, the concentration of A and B changes to '1-x', as product produces is referred to be 'x'.
As we know, the product is of two moles therefore x=2…
Now, Equilibrium constant (k) is the ratio of product of concentration of product to the product of concentration of reactants at equilibrium.
K = [C]² / [A][B]
K = x² / (1-x)(1-x)
K = 2² / (1–2)(1–2)
So, K=4
The unit of Equilibrium constant depends upon the product and reactants, therefore in this case there is no unit.
Let's consider A+B=C a reversible reaction.
Let the initial concentrations of A and B be '1'. There will be ‘0’ concentration of product as the state is initial.
Now at equilibrium, the concentration of A and B changes to '1-x', as product produces is referred to be 'x'.
As we know, the product is of two moles therefore x=2…
Now, Equilibrium constant (k) is the ratio of product of concentration of product to the product of concentration of reactants at equilibrium.
K = [C]² / [A][B]
K = x² / (1-x)(1-x)
K = 2² / (1–2)(1–2)
So, K=4
The unit of Equilibrium constant depends upon the product and reactants, therefore in this case there is no unit.
Similar questions