Question

one mole of an ideal monatomic gas requires 207 joule heat to raise the temperature by 10 Kelvin when heated at constant pressure. if the same gas is heated at constant volume to raise the temperature by the same 10 Kelvin, the heat required is

Answer 1

Hii dear,

# Answer- 124 J

# Given-

dT=10°K

R=8.3J/mole°K

Qp=207J

n=1

# Formula-

For one mole of an ideal monoatomic gas

Cp-Cv=R

But heat at constant pressure is given by,

Qp=n×Cp×dT

207=1×Cp×10

Cp=20.7J

Also heat at constant volume is given by,

Qv=n×Cv×dT

Qv=1×(Cp-R)×dT

Qv=(20.7-8.3)10

Qv=12.4×10

Q=124J

Heat at constant volume to raise temperature by 10°K is 124J.

Answer 2

# Given-

dT=10°K

R=8.3J/mole°K

Qp=207J

n=1

# Formula-

For one mole of an ideal monoatomic gas

Cp-Cv=R

But heat at constant pressure is given by,

Qp=n×Cp×dT

207=1×Cp×10

Cp=20.7J

Also heat at constant volume is given by,

Qv=n×Cv×dT

Qv=1×(Cp-R)×dT

Qv=(20.7-8.3)10

Qv=12.4×10

Q=124J

Heat at constant volume to raise temperature by 10°K is 124J.