one mole of ideal gas expands from initial volume V1 = V final volume is V2= 10V we at a constant temperature the T =300K if R is equal to 8.3 j mol‐¹kg‐¹ calculate the amount of heat absorbed by the gas.
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Explanation:
1728 joules
Given: T=300K,V
1
=10L,V
2
=20L
according to the isothermal process, work done is given by
W
iso
=μRTlog
e
V
1
V
2
=1×8.31×300log
e
10
20
=1728J
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