Question

one mole of monoatomic gas 5/3 is mixed with 2 mole of diatomic gas 7/5​

Answer 1

Answer:

hope it helps uu

Explanation:

For a monoatomic gas:

Cv=23R

For a diatomic gas:

Cv=25R

Thereofore Cvavg=223R+25R=2R

Also Cp=Cv+R

⟹Cpavg=3R

⟹γ=CvavgCpavg=23