Question

One mole of solid iron was vaporized in an oven at its boiling point of 3433 K and enthalpy of vaporization of iron is 344.3 kJ mol⁻¹. The value of entropy vaporization (in J mol⁻¹) of iron is
(a) 100
(b) 10
(c) – 100
(d) 110

Answer 1

answer : option (a) 100

One mole of solid iron was vaporized in an oven at its boiling point of T_b = 3443 K and enthalpy of vaporization of iron is ∆H_vap = 344.3 kJ/mol/K

entropy is the ratio of heat to the temperature.

i.e., S = ∆H_vap/T_b

= 344.3kJ/mol/K/3443

= 344.3 × 1000/3443 J/mol

= 3443 × 100/3443 J/mol

= 100 J/mol

hence entropy of vaporisation of iron is 100 J/mol. therefore, option (a) is correct choice.

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Answer 2

Explanation:

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