Question

The enthalpies of the following reactions are shown below
$\frac{1}{2} H_2(g) + \frac{1}{2} O_2(g) \rightarrow OH(g)$ ; $\Delta H$ = 42.09 kJ mol⁻¹
$H_2(g) \rightarrow 2H(g)$ ; $\Delta H$ = 435.89 kJ mol⁻¹
$O_2(g) \rightarrow 2O(g)$ ; $\Delta H$ = 495.05 kJ mol⁻¹
Calculate the O –– H bond energy for the hydroxyl radical.
(a) 223.18 kJ mol⁻¹
(b) 423.38 kJ mol⁻¹
(c) 513.28 kJ mol⁻¹
(d) 113.38 kJ mol⁻¹

Answer 1

Answer is 113.38 kJ mol-¹

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Answer 2

Explanation:

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(d) 113.38 kJ mol⁻¹