One morning walk three person steps measure 40 cm,42cm,45cm. what is minimum distance each should walk so that each cover the distance
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Lcm of 40,42,45 cm is 2520 cm.
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We have to find a Lcm of the given numbers.
The minimum distance that they all three should walk will be the L.C.M. of 40, 42, 45.
40=2×2×2×5
42=2×3×7
45=3×3×5
Hence L.C.M. of 40, 42 and 45 = 2×2×2×3×3×5×7= 2520cm = 25.20m
minimum distance each should walk so that each cover the distance is 25.20m
The minimum distance that they all three should walk will be the L.C.M. of 40, 42, 45.
40=2×2×2×5
42=2×3×7
45=3×3×5
Hence L.C.M. of 40, 42 and 45 = 2×2×2×3×3×5×7= 2520cm = 25.20m
minimum distance each should walk so that each cover the distance is 25.20m
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