Math, asked by shrugodase7711, 3 months ago

One no. is smaller than other 4 and product of these two no. is 40 ,then the quadratic equations formed is ?​

Answers

Answered by aslamm
0

Answer:

Solution :

Let  x  and  y  be the numbers.

One number is 3 less than another number  ⟹   x−y=3  

Product is 40  ⟹x∗y=40  

x−y=3−(1)  

x∗y=40⟹x=40y−(2)  

Substituting (2) in (1)

40y−y=3  

40−y2=3y  

y2+3y−40=0  

The above quadratic equation can be solved using the formula -

y=−b±b2−4ac√2a  

where a = 1, b=3 and c=-40

∴,y=−3±32−4∗1∗(−40)√2∗1  

y=−3±9+160√2  

y=−3±132  

y=5,−8  

If  y=5,x=405=8  

If  y=−8,x=40−8=−5  

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Lukas Schmidinger, I have passed some math courses in university.

Answered June 5, 2019

One number is 3 less than another number if their product is 40,what are the numbers?

y=x−3  

xy=40  

Combining this gives us the quadtric equation:

x2−3x−40=0  

Using the quadtric formula  ax2+bx+c=0⟹x=−b±b2−4ac√2a  

We get −5  and  8  thus  y=−8  and  5 .

There are two solutions  {−8,−5}  and  {5,8} .

730 views

B.L. Srivastava, M.Sc.Ph.D. Mathematics, Chhatrapati Shahu Ji Maharaj University

Answered June 5, 2019

Let the two numbers be a, b ,then according to the problem (a + 3) = b and (a·b) = 40 . From these two relations , we get, a·(a + 3) = 40 or a^(2) + 3a - 40 = 0 ==> (a - 5)(a + 8) = 0 ==> a = 5 , -8 which in turn gives b = 8 , - 5 respectively . Thus there are two pairs of such numbers & tthese are (a, b) = (5, 8) and (-8, -5) .

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More Answers Below

One number is 3 less than another number. If the sum of the two numbers is 177, what is each number?

Which number is 40% less than 80?

If 3/4 of a number is 3/4 less than that number, what is the number?

Federico Tancinco, former Purchasing Manager / Math Analyst

Answered June 5, 2019

answer: (-5, -8) & (5, 8)

Let x = 1st number

x-3 = 2nd number

x(x - 3) = 40 ; expand and combine terms

x^2 - 3x - 40 = 0 ; get the factor

(x - 8)(x + 5) = 0 ; equate to get values of x

x - 8 = 0 ; x + 5 = 0

then: x = {-5, 8}

when x = -5 :

x - 3 = -5 - 3 = -8

when x = 8

x - 3 = 8 - 3 = 5

1.5K views

James Wright, BS Physics & Mathematics, University of Illinois at Chicago (1972)

Answered June 9, 2019

Suppose a = b-3, and b(b-3) = 40, then b^2 - 3b = 40, which, when rearranged, becomes

b^2 - 3b - 40 = 0 or (b-8)(b+5) = 0 so b = +8 or -5

The only value of b that is a possible solution is b = 8, making a = 5. The numbers asked for are 8 and 5.

142 views

Shivani Pandey

Answered June 5, 2019

the answer would be 8 and 5

x-y=3

x*y=40

x=40/y

40/y - y =3

y^2 +3y -40=0

y^2 +8y -5y -40=0

Y-5=0 & Y+8=0

Y=5

X=3

173 viewsView Upvoters

Gerry Hardy

Answered June 5, 2019

8x5= 40

94 views

John Kinsella, Lecturer (2005-present)

Answered June 7, 2019

5 and 8

88 views

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Step-by-step explanation:

Answered by parth07sg
2

Step-by-step explanation:

 {x}^{2}  + 4x - 40 = 0

it's helpful

thank and follow

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