one number exceeds another by 36. if sum of both number is 48. find the numbers
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Answered by
47
Let one number be x
then the other number is x+36
Sum of two numbers = 48
x + x + 36 = 48
2x + 36 = 48
2x = 48-36
2x = 12
x = 12/2=6
The other number = 6+36 = 42
Therefore, the two numbers are 6 and 42
then the other number is x+36
Sum of two numbers = 48
x + x + 36 = 48
2x + 36 = 48
2x = 48-36
2x = 12
x = 12/2=6
The other number = 6+36 = 42
Therefore, the two numbers are 6 and 42
Answered by
22
one number =x
other number =X+36
sum of two number ia given as 48
so, x+x+36=48
2x+36=48
2x=12
x=6
therefore other number is 6+36 =42
so the rwo numbers are 6 and 42
other number =X+36
sum of two number ia given as 48
so, x+x+36=48
2x+36=48
2x=12
x=6
therefore other number is 6+36 =42
so the rwo numbers are 6 and 42
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