one number is 10 more than the other if their sum is 52 find the numbers
Answers
Answered by
323
let one number be x.
then other number be x+10
A/Q
x+x+10=52
2x=52-10
2x=42
x=42÷2
x=21
therefore one no.=21
and other no.=21+10=31
then other number be x+10
A/Q
x+x+10=52
2x=52-10
2x=42
x=42÷2
x=21
therefore one no.=21
and other no.=21+10=31
SARDARshubham:
hey, it's 52 not 54
Answered by
49
Let the two numbers be a & b ;
then according to the question ,
--------------------
a-b = 10
a+b = 52
a = 10+b
a = 52-b
______________
10+b = 52-b
b+b = 52-10
2b = 42
b = 21
a = 10+b
a = 10+21
a = 31
=================
Hence the numbers are 21 & 31.
then according to the question ,
--------------------
a-b = 10
a+b = 52
a = 10+b
a = 52-b
______________
10+b = 52-b
b+b = 52-10
2b = 42
b = 21
a = 10+b
a = 10+21
a = 31
=================
Hence the numbers are 21 & 31.
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