Question

one number is 3 less than two times the other, if there sum is increased by the 7 the result is 37 then the number are options are a=9,21 b=21,4. c=11,19 d=7,3. answer is 11,19. but i want solution​

Answer 1

Answer:

Option(C)

Step-by-step explanation:

Let the numbers be x and y.

(i) One number is 3 less than 2 times other.

y = 2x - 3.

(ii) Sum is increased by 7, the result is 37.

⇒ x + y + 7 = 37

⇒ x + 2x - 3 + 7 = 37

⇒ 3x + 4 = 37

⇒ 3x = 33

⇒ x = 11

Substitute x = 11 in (i), we get

⇒ y = 2x - 3

⇒ y = 2(11) - 3

⇒ y = 19.

Therefore, the values are 11 & 19.

Hope it helps!

Answer 2

Let one number = x

Let the other number = 2x - 3

Set up equation.

[x + (2x - 3)] + 2 = 8

[x + 2x - 3] + 2 = 8

3x - 1 = 8

3x = 9

 x = 3

Substitute this value of x into the variables.

One number is 3 and the other is 3.

Let's check these numbers to see if they satisfy the statement.

3 + 3 = 6

Take this sum and increase it by 2.

6 + 2 = 8

The final result is 8.  Therefore, the two numbers are 3 and 3.