Question

one number is 3 less than two times the other number.If their sum is increased by 7,the result is 37.Find the number.

Answer 1

let number be=x
other number=2x-3
x+2x-3+7=37
x+2x-3=30
3x-3=30
3x=33
x=11

Answer 2

let the other number be x. Then, the one number =2x-3 according to question, 2x-3+x+7=37 3x+4=37 3x=37-4 x=33÷3 x=11 Then, the one number =2x-3 =19