Question

one number is 4 less than 3 times a second number. If 3 more than twice the first number is decreased by the second, the result is 11. Find both numbers
please help me i need this tonight!

Answer 1

Answer:

Let x = "one number"

Let y = "a second number"

:

Write an equation for each statement:

:

"one number is 4 less than 3 times a second number."

x = 3y - 4

:

"if 3 more than twice the first number is decreased by twice the second, the result is 11."

2x + 3 - 2y = 11

2x - 2y = 11 - 3

2x - 2y = 8

:

Replace x with (3y-4) from the 1st statement, and solve for y

2(3y-4) - 2y = 8

6y - 8 - 2y = 8

4y = 8 + 8

4y = 16

y = 4

:

x = 3(4) - 4

x = 8